Sold

280 41st Street, Oakland, CA

Oakland · Alameda County · Sold for $1,300,000 on September 22, 2022 (listed at $995,000)

280 41st Street is a 3 bedroom, 2.5 bath, ±1,799 sq ft single-family home in Oakland, California, built in 1900 on a 4,410 sq ft lot. It sold for $1,300,000 on September 22, 2022 (about $723 per sq ft), after listing at $995,000. Patrick MacCartee of The Grubb Company represented the buyer.

Key facts

Address280 41st Street, Oakland, CA
StatusSold September 22, 2022
Sold price$1,300,000 (~$723 per sq ft)
List price$995,000
Sale-to-list ratio131%
Days on market15
Property typeDetached single-family home
Bedrooms / bathrooms3 bedrooms / 2.5 bathrooms
Living area±1,799 sq ft (public records)
Lot size4,410 sq ft (0.10 acre)
Year built1900
ParkingNo garage
CountyAlameda
RepresentationPatrick MacCartee, The Grubb Company, represented the buyer

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Frequently asked questions

What did 280 41st Street sell for?

280 41st Street sold for $1,300,000 on September 22, 2022, about $723 per square foot based on approximately 1,799 square feet. It was listed at $995,000.

How big is the lot, and is there parking?

4,410 sq ft (0.10 acre). No garage.

Who represented the buyer in the sale of 280 41st Street?

Patrick MacCartee of The Grubb Company (DRE #02142693) represented the buyer. Contact: 510-859-4895, [email protected].

Buyer's agent: Patrick MacCartee, The Grubb Company · DRE #02142693
510-859-4895 · [email protected] · realtor510.com
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Last updated September 27, 2026. Information deemed reliable but not guaranteed. Square footage is approximate and from public records. Based on information from bridgeMLS; buyers should independently verify all information, including school assignments, and conduct their own inspections.